997. Find the Town Judge
1. Question
In a town, there are n
people labeled from 1
to n
. There is a rumor that one of these people is secretly the town judge.
If the town judge exists, then:
- The town judge trusts nobody.
- Everybody (except for the town judge) trusts the town judge.
- There is exactly one person that satisfies properties 1 and 2.
You are given an array trust
where trust[i] = [ai, bi] representing that the person labeled ai trusts the person labeled bi.
Return the label of the town judge if the town judge exists and can be identified, or return -1
otherwise.
2. Examples
Example 1:
Input: n = 2, trust = [[1,2]]
Output: 2
Example 2:
Input: n = 3, trust = [[1,3],[2,3]]
Output: 3
Example 3:
Input: n = 3, trust = [[1,3],[2,3],[3,1]]
Output: -1
3. Constraints
1 <= n <= 1000
- 0 <= trust.length <= 104
trust[i].length == 2
- All the pairs of
trust
are unique. - ai != bi
- 1 <= ai, bi <= n
4. References
来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/find-the-town-judge 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
5. Solutions
理解成有向图,则法官的入度为n-1,出度为0.
class Solution {
public int findJudge(int n, int[][] trust) {
int[] in = new int[n + 1];
int[] out = new int[n + 1];
for(int[] arr : trust) {
out[arr[0]]++;
in[arr[1]]++;
}
for(int i = 1; i <= n; i++) {
if(in[i] == n - 1 && out[i] == 0) {
return i;
}
}
return -1;
}
}